Using standard formulae, derive an expression for the final speed of a falling object in terms of its change in height. Assume zero air resistance or other resistive forces.

Ek = (1/2)mv2

Ep = mg(dh)

Set these equal to each other, because of conservation of energy:

(1/2)mv2 = mg(dh)

Cancel the mass:

(1/2)v2 = g(dh)

v2 = 2g(dh)

v = (2g(dh))1/2

Answered by Danny L. Physics tutor

1467 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

How to find wave speed from frequency and wave length.


A stone is thrown from the top of a cliff. When is its mechanical energy higher, at the top of the cliff right before being thrown or right before hitting the ground?


What is the conservation of energy?


What are some key differences between sound and light waves?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy