Using standard formulae, derive an expression for the final speed of a falling object in terms of its change in height. Assume zero air resistance or other resistive forces.

Ek = (1/2)mv2

Ep = mg(dh)

Set these equal to each other, because of conservation of energy:

(1/2)mv2 = mg(dh)

Cancel the mass:

(1/2)v2 = g(dh)

v2 = 2g(dh)

v = (2g(dh))1/2

DL
Answered by Danny L. Physics tutor

2433 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is meant by terminal velocity?


A cyclist travels along a straight flat road. Describe the condition required for the cyclist to continue traveling along the road at a constant speed. How does this condition change if the cyclist travels up a slope?


If a car sets off from rest with a constant acceleration of 3 m/(s^2), what would its speed be after 5 seconds?


How does electromagnetic induction produce a current?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning