Prove that tan^2(x)=1/(cos^2(x))-1
tan^2(x)=1/(cos^2(x))-1 Left hand side of the equation (LHS)=tan^2(x) Use the identity tan(x)=sin(x)/cos(x) and substitute it into the LHS LHS=sin^2(x)/cos^2(x) Use the identity sin^2(x)+cos^2(x)=1 and rearrange to make sin^2(x) the subject sin^2(x)=1-cos^2(x) Substitute this into the LHS: sin^2(x)/cos^2(x)=1-cos^2(x)/cos^2(x) Simplify this to give the RHS of the equation given:1-cos^2(x)/cos^2(x)=1/(cos^2(x))-1 Therefore the LHS=RHS
PA
Answered by Phoebe A. • Further Mathematics tutor
2835 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Prove that sin(x)^2 - 5cos(x)^2 = 6sin(x)^2 - 5
Why is it that when 'transformation A' is followed by 'transformation B', that the combined transformation is BA and not AB?
Solving equations with unknown in both sides
Work out the gradient of the curve y=x^3(x-3) at the point (3,17)