25985 questions

How do i know what the major and minor products of the reaction between Hydrogen Bromide and Propene would be?

We would use something called Markovniov's rule. Essentially, the H+ ion (or proton) that is attracted to the electron dense double bond of the alkene, is added to the carbon that has the most Hydrogen atoms bonded to it. This creates the more stable carbocation intermediate (in this case a secondary carbocation) which has a lower activation energy, and therefore a faster reaction, hence a more favoured product. In this case, 2-Bromopropane is the major, and 1-Bromopropane is the minor product
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David Q.

Answered by David, Chemistry A Level tutor with MyTutor

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The Curve C shows parametric equations x = 4tant and y = 5((3)^1/2)(sin2t) , Point P is located at (4(3)^1/2, 15/2) Find dy/dx at P.

First I would find the value of t at Point P - I would equate the x equation to 4(3)^1/2 and the y equation to 15/2. This would give me (Px,Py). After this I would then find dy/dt, and dx/dx by differentiating the two equations with respect to t. We can then find dy/dx by multiplying dy/dt by dt/dx ( we obtain dt/dx by finding the reciprocal of dx/dt ). With this we have an equation for dy/dx , now all we have to is substitue the value of t we found in the beginning to obtain dy/dx.
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Arjun B.

Answered by Arjun, Maths A Level tutor with MyTutor

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Make x the subject of the formula: x/2 + 3 = y - 2

To make x the subject of the formula, we simply want to have x on its own on one side of the equals sign. So we need to remove any numbers on the same side as x. Everything we do to the left hand side we must also do exactly the same to the right hand side. Firstly, we want to remove the 3 on the left hand side, so subtract 3 from both sides to give: x/2 + 3 - 3 = y - 2 -3 which is x/2 = y - 5. Now we want to remove the divide by 2 on the left hand side so we need to do the opposite of division which is multiplication. So we multiply both sides by 2 to give: x = (y - 5)*2. We use the brackets as both y and -5 are multiplied by 2. Expanding the brackets then gives usx = 2y - 10
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Katie L.

Answered by Katie, Maths GCSE tutor with MyTutor

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How do I do well in the UCAT?

The UCAT is very different to A levels or GCSEs.  Whilst these exams are ones you may have to revise a lot of content for, success in the UCAT comes from practice and having the right exam techniques. Each of the sections in the UCAT has a different purpose and hence can be approached differently; its useful to keep this in mind so you can prepare for each accordingly. Something which applies to most sections, however, is the time pressure. When doing the UCAT, it’s important that you don’t deliberate your answer to every question as otherwise its likely you will run out of time. Practicing doing questions of each section will help you answer questions more efficiently. It’s also useful to practice doing the entire test without taking breaks, as you’ll have to do in the real thing – staring at a screen for two hours straight is more difficult than it sounds!  
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Tanya S.

Answered by Tanya, UCAT University tutor with MyTutor

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How do I do well in the UCAT?

The UCAT is very different to A levels or GCSEs.  Whilst these exams are ones you may have to revise a lot of content for, success in the UCAT comes from practice and having the right exam techniques. Each of the sections in the UCAT has a different purpose and hence can be approached differently; its useful to keep this in mind so you can prepare for each accordingly. Something which applies to most sections, however, is the time pressure. When doing the UCAT, it’s important that you don’t deliberate your answer to every question as otherwise its likely you will run out of time. Practicing doing questions of each section will help you answer questions more efficiently. It’s also useful to practice doing the entire test without taking breaks, as you’ll have to do in the real thing – staring at a screen for two hours straight is more difficult than it sounds!  
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Tanya S.

Answered by Tanya, UCAT University tutor with MyTutor

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When are the conditional and future tenses used in French?

The conditional tense is a tense that is linked to the English "would". It expresses a possible result which relies on a condition. An example of this would be "I would have a lie-in everyday, if I didn't have to go to college." ("Je ferais la grasse matinée tous les jours, si je ne devais pas aller au collège.") In this sentence, we can see that there is a condition to this tense, introduced by "si". The future tense is a tense which explains something that is more certain, with no conditions attached. An example of this would be "Since I don't have lessons tomorrow, I'll have a lie-in." ("Puisque je n'ai pas de leçons demain, je ferai la grasse matinée.") In this sentence, the fact that the speaker will have a lie-in the next day is certain, so they use the future tense which is more certain.
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Thomas S.

Answered by Thomas, French A Level tutor with MyTutor

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When working with probabilities why is it sometimes necessary to add and sometimes to multiply?

Whether you need to add or multiply depends on whether it is a case of 'AND' or 'OR'. For 'AND' you multiply, and for 'OR' you add. Below are examples of each case, using dice as an example:
To calculate the probability that I get a six on my first roll AND get a five on my second roll, I need to multiply: 1/6 x 1/6 = 1/36
To calculate the probability that I get either a six OR a five on my first roll, I need to add: 1/6 + 1/6 = 2/6 = 1/3





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Marcus W.

Answered by Marcus, Maths GCSE tutor with MyTutor

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Factorise X^2 + 13x + 42; from this, please give the answer to X^2 + 13x + 42 = 0

This question aims to look at quadratic equations. We factorise Quadratic equations into two sets of bracketsFirst, we are dealing with X2. X2 is formed from X multipled by X, so each bracket should contain one X --> (X+?) (X+?)The aim here is to find two numbers which add up together to give 13 and Multiply to give a product of 42. Considering the sum of the numbers is not large, this means the numbers themselves are not large too!Thinking about which numbers Multiply to give 42 --> 1 x 42, 2 x 21, 3 x 14, 6 x 7Now look above, which numbers above give a sum of 13? --> 6 & 7!This means (X+6) (X+7) --> X2 + 13x + 42Now if we make this equation equal to 0 --> (X+6) (X+7) = 0; here we get two answers --> X is either -6 or -7We can try putting either one of these numbers in the place of X and find the answer will be equal to 0, Try it out!

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Khalid A.

Answered by Khalid, Maths GCSE tutor with MyTutor

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