An electrical heater supplies 500J of heat energy to a copper cylinder of mass 32.4g Find the increase in temperature of the cylinder. (Specific heat capacity of copper = 385 J*kg^-1*Celsius^-1

The temperature of a body of mass m and specific heat capacity c rises by change in temperature (delta)T when an amount of heat Q is added to it (Q = mc(delta)T). From the equation we see that the change in temperature is simply equal to the heat divided by the mass times the specific heat capacity of copper ((delta)T = Q / m*c). Now we can just plug in the numbers to find the answer. (Note that the mass is not given in SI units and we have to convert it 32.4g = 0.0324kg). From here follows that the increase in temperature is equal to 500 / 0.0324 * 385 or 40.0834, which we can round to 40.1 degrees Celsius.

VB
Answered by Viktoria B. Physics tutor

8906 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

What is the root mean square voltage of an alternating current?


A 12V lamp, 36W is switched on for 1 hour. Find the energy supplied by the battery.


Using Newton's law of universal gravitation, show that T^2 is proportional to r^3 (where T is the orbital period of a planet around a star, and r is the distance between them).


Describe the workings behind the Photoelectric effect


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning