An electrical heater supplies 500J of heat energy to a copper cylinder of mass 32.4g Find the increase in temperature of the cylinder. (Specific heat capacity of copper = 385 J*kg^-1*Celsius^-1

The temperature of a body of mass m and specific heat capacity c rises by change in temperature (delta)T when an amount of heat Q is added to it (Q = mc(delta)T). From the equation we see that the change in temperature is simply equal to the heat divided by the mass times the specific heat capacity of copper ((delta)T = Q / m*c). Now we can just plug in the numbers to find the answer. (Note that the mass is not given in SI units and we have to convert it 32.4g = 0.0324kg). From here follows that the increase in temperature is equal to 500 / 0.0324 * 385 or 40.0834, which we can round to 40.1 degrees Celsius.

VB
Answered by Viktoria B. Physics tutor

8449 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Why does a single slit diffraction pattern occur?


What are the differences between standing waves and progressive waves?


A car is travelling at 20 m/s. The accelerator is applied, causing an acceleration of 2m/s^s. How fast is the car travelling after 10 seconds of acceleration?


Calculate the length of a 120m (as measured by the astronaut) spaceship travelling at 0.85c as measured by a stationary observer


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences