An electrical heater supplies 500J of heat energy to a copper cylinder of mass 32.4g Find the increase in temperature of the cylinder. (Specific heat capacity of copper = 385 J*kg^-1*Celsius^-1
The temperature of a body of mass m and specific heat capacity c rises by change in temperature (delta)T when an amount of heat Q is added to it (Q = mc(delta)T). From the equation we see that the change in temperature is simply equal to the heat divided by the mass times the specific heat capacity of copper ((delta)T = Q / m*c). Now we can just plug in the numbers to find the answer. (Note that the mass is not given in SI units and we have to convert it 32.4g = 0.0324kg). From here follows that the increase in temperature is equal to 500 / 0.0324 * 385 or 40.0834, which we can round to 40.1 degrees Celsius.
VB
Related Physics A Level answers
All answers ▸For 100ml of a liquid with a mass density of 1(kg m^-3), and a specific heat capacity of 2(kJ kg^-1 K^-1), how much energy is required to increase the temperature of the liquid by 4 degrees celsius. Assume no heat loss and that the liquid does not boil.
If a bulb has a current of 20mA and voltage of 5V, and the current cost of electricity is £3 for a kW/hour. How much money would you spend to power the bulb for 8 hours? Are these good estimates for the current, voltage and cost of electricity?
Explain what is meant by the mass defect of an atomic nucleui
A geostationary satellite is orbiting Earth, a) What is meant by a geostationary orbit? b) Calculate the height at which the satellite orbits above the surface of the Earth. The radius of the Earth is 6400km and its mass is 6x10^24 kg.