When 0.81 m of a wire with cross-sectional area of 3.1*10^-11 m^2 is connected across a 2 V battery a current of 1.6 A flows in the wire. Find the resistivity of the material of the wire.
The resistance in the wire is given by the resistivity of the material by the lenght and divided by the cross-sectional area (R = pL/A). From here we can rearrange and have p = RA/L. However, we also know that R = V/I, and thus, our final formula becomes p = VA / IL. Plugging in the numbers we get p = 23.110^-11 / 1.60.81, which is equal to 4.7839510^-11, or rounding, 4.8*10^-11 Ohm-meters.
VB
Related Physics A Level answers
All answers ▸When does a pendulum bob move fastest and why?
How many joules of heat energy are required to raise the temperature of 10kg of water from 22⁰C to 27⁰C? (The Specific Heat Capacity of water is 4200 Jkg^-1⁰C^-1)
A ball is launched from ground level at 5m/s at an angle of 30 degrees above the horizontal. What is its height above ground level at the highest point in its trajectory?
A Uranium-(238,92) nucleus decays into a Thorium-234 nucleus by the emission of an alpha-particle. Given Thorium has a chemical symbol Th build a nuclear equation.