Manually implement a function that finds the smallest value in a list of integers and print it.

def findMin(list): min = list[0] for i in range(1, len(list)): if list[i] < min: min = list[i] print(min)

DH
Answered by Daniel H. Python tutor

2154 Views

See similar Python Mentoring tutors

Related Python Mentoring answers

All answers ▸

Given a list of N numbers, use a single list comprehension to produce a new list that only contains those values that are: (a) even numbers, and (b) from elements in the original list that had even indices .


Sort a given input of lowercase letters alphabetically


Sales is real Customers is integer startmainprog input Sales input Customers if ((Sales > 500) OR ((Sales > 300) AND (Customers>9))) then output “Bonus Awarded” else output “No Bonus” end if end subroutine. Sales = 600 Customers = 9, answer:


Whats the output of "for i in "hello world": print(i)" and why/how is this achieved


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences