The braking distance of a road train travelling at 15m/s is 70m. Assuming that the same braking force is applied at all speeds, show that the braking distance of a road train when travelling at 25m/s is about 190m.

Energy = force x distance and Energy = 0.5 x mass x velocity squared

Hence, force = (0.5 x mass x velocity squared) / distance --- (equation 1) This applies for both situation A and B, and given that force is stated to be the same in each case, and mass is the same, we can equate eqn 1 for each.

Hence, (0.5 x mass x velocity(A) squared) / distance(A) = (0.5 x mass x velocity(B) squared) / distance(B)

and so distance(B) = (velocity(B) squared x distance(A)) / (velocity(A) squared) = (25^2 x 70) / 15^2 = 194m

JJ

Related Physics A Level answers

All answers ▸

Show that the radius of an orbit may be expressed as follows: R^3=((GM)/4*pi^2)T^2


How would I resolve forces on a slope?


How does the strong nuclear force between two nucleons varies with separation of the nucleons. Please detail the range over which the force acts.


State the principle of superposition of waves and illustrate it schematically.