How can I find the explicit formula for the inverse of sinh?

Write y = sinh^(-1)(x) ie x = sinhy. Then writing this in terms of exponentials and multiplying by 2 we will get 2x = exp(y) - exp(-y). Multiply by exp(y) and rearrange to obtain exp(2y) - 2xexp(y) -1 = 0. Then this is is simply a quadratic in exp(y), so using the quadratic equation or completing the square we get exp(y) = x + sqrt(x^2 +1). Notice we take the positive square root since we must have exp(y) > 0. Then simply take logs of both sides to get the equation for y in terms of x. This is now the inverse of sinh.

SG
Answered by Stefan G. Further Mathematics tutor

2721 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

I do not understand this topic and particularly this example. In the class the result was found out but I still do not get it. How did the teacher came up with this outcome?


find general solution to: x(dy/dx) + 2y = 4x^2


Calculate: ( 2+i√(5) )( √(5)-i).


For f(x) = (3x+4)^(-2), find f'(x) and f''(x) and hence write down the Maclaurin series up to and including the term in x^2.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences