What is electromotive force and how is it different to potential difference?

The electromotive force or emf of a cell in a circuit is, for a start, not a force at all: it has the unit of volts. A good definition is ‘the power supplied by the cell per unit current through the cell’ or, equivalently, ‘the energy supplied by the cell per unit charge through the cell’ (IB examiners love to ask for this by the way). When the internal resistance of a cell is zero (or negligible), the emf is exactly the same as the potential difference (or voltage) between the terminals of the cell. But this changes when the internal resistance is significant – this is the resistance inside the actual cell which will ‘use up’ some of the emf before the current even leaves the cell. Since V = IR, you can find the potential difference across this internal resistance by multiplying the resistance by the current through it. Taking away this value from the emf will give you the remaining potential difference between terminals of the cell.

TB
Answered by Tom B. Physics tutor

10720 Views

See similar Physics IB tutors

Related Physics IB answers

All answers ▸

How much velocity should a small toy rocket, weighing 10kg, acquire in order to escape the Earth's gravitational field? (Neglect any type of friction with the atmosphere)


Which unit is equivalent to J kg^-1? a) m s^-1 b) m s^-2 c) m^2 s^-1 d) m^2 s^-2


A ball of mass m with initial velocity u rebounds from a wall, with final velocity v. Using Newton's laws of motion explain forces acting in the system.


The diagram below represents a balloon just before take-off. The balloon’s basket is attached to the ground by two fixing ropes.Calculate the tension in either of the fixing ropes.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning