A block of ice slides down the full height from one side of a 1m high bowl and up the other side. Assuming frictionless motion and taking g as 9.81ms-2, find the speed of the block at the bottom of the bowl and the height it reaches on the the other side.
Using the law of conservation of energy, the potential energy of the block is transferred to kinetic energy as it slides down. KE [0.5mv2] = PE [mgh], v = √2gh v = √29.811 = 4.43 ms-1 The block's KE will be transferred back to PE as it rises so it will slide up to the same height it slid down from - 1m.
OS
Related Physics A Level answers
All answers ▸A small ball of mass 150 g is placed at a height of 20cm above the ground on an incline of 35°. It is released and allowed to roll down the slope; what will be the ball's speed when it reaches the ground? Assume friction and air resistance can be ignored.
Do heavier objects fall on the ground quicker?
Find an expression for the escape velocity of a test object.
Is light the fastest? if no, then explain quantum entanglement!