Differentiate arctan of x with respect to x.
Say arctan of x is equal to a value y. Now take the tangent of both sides; x now equals tan of y! Easy from here, differentiate both sides wrt x. Now 1 equals sec^2y dy/dx, and you can rearrange to find dy/dx. To simplify, use the trig identity tan^y+1=sec^y, to get 1/1+x^2 is dy/dx.
AM
Answered by Andrew M. • Further Mathematics tutor
4219 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸z = 50 / (3+4i). What is z in a+bi form?
How do you deal with 3 simultaneous equations? (Struggling with Q7 of AQA specimen paper 1)
Find the Taylor Series expansion of tan(x) about π/4 up to the term in terms of (x-π/4)^3.
prove by induction that, f(n) = 2^(3n+1) + 3(5^(2n+1)) is divisible by 17 for all n>0.