Differentiate arctan of x with respect to x.

Say arctan of x is equal to a value y. Now take the tangent of both sides; x now equals tan of y! Easy from here, differentiate both sides wrt x. Now 1 equals sec^2y dy/dx, and you can rearrange to find dy/dx. To simplify, use the trig identity tan^y+1=sec^y, to get 1/1+x^2 is dy/dx.

AM
Answered by Andrew M. Further Mathematics tutor

3473 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Find the inverse of the general 2x2 matrix A= ([a, b],[c, d]) when does this inverse exist?


z = 50 / (3+4i). What is z in a+bi form?


Given z=cosx+isinx, show cosx=1/2(z+1/z)


What is sin(x)/x for x =0?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning