At a stationary point of y, dy/dx = 0.Step 1: Let's find dy/dx first by differentiating. To differentiate the product of two functions, we can use the product rule:d(fg)/dx = f * dg/dx + df/dx * g. So dy/dx = d(e^2x cos x)/dx = (e^2x) * (-sin x) + (2e^2x) * cos x = 2e^2x cos x - e^2x sin x.Step 2: Now we've found dy/dx, we can set it to 0. So we can set 2e^2x cos x - e^2x sin x = 0. Therefore 2e^2x cos x = e^2x sinx. We can cancel e^2x from each side because it is never equal to zero, therefore 2cos x = sin x. Dividing by cos x gives 2 = tan x. We can use arctan now to find x: arctan 2 = arctan(tan x) = x. Now finally we know x, so we can find y by plugging into our original equation: y = e ^ (2*arctan2) * cos (arctan2) = 4.09

(5 + 2(2^0.5))(7 - 3(2^0.5))

Related Maths A Level answers

Find the area enclosed between the curves y = f(x) and y = g(x)

How do I calculate the reactant forces for the supports of the beam where the centre of mass is not same distance from each support?

How can I find the stationary point of y = e^2x cos x?

Differentiate the following equation: y = 2(x^3) - 6x

We're here to help

Company Information

Popular Requests

© MyTutorWeb Ltd 2013–2025

CLICK CEOP