There is a point between the Moon and the Earth where the gravitational attractions are equal and opposite. How much further is this point from the Earth than the Moon

Using the formula for gravitational attraction between the Moon/Earth and a test mass, m. We determine FE = (G*ME m)/(rE2 ), FM = (GMM*m )/ (rM2). Setting these two forces equal to each other and rearranging gives us the formula: rM2 = (MM/ME ) * rE2. Taking the square root of both sides, and noting the distances, r, should always be positive we get distance from the Earth is sqrt(MM/ME). 

PD
Answered by Paul D. Physics tutor

7310 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

An electron is traveling at a velocity of 500m/s perpendicular to a uniform magnetic field. A force of magnitude 4.32 x10^(-16) N is acting on the electron, what is the magnetic flux density of the field?


A ball is thrown up with an initial velocity of 8 m/s and initial height of 1.5m above the ground. Calculate the maximum height the ball reaches and the time it takes to get there.


A cannon ball is shot at an angle of 60 degrees from a cliff of height 50m, if it's inital speed is 20ms^-1 what horizontal distance does it travel before hitting the ground.


A cyclist rides 10km. In the first 5km, they climb a hill, averaging 10km/h. In the second 5km, they descend the hill, averaging 30km/h. What is their average speed over the full 10km?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning