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In simple harmonic motion, where would the object have the largest speed. If the angular velocity is 2 rad s^-1, and the amplitude is 1m, what is the largest speed obtained by the object?

The largest speed is obtained at the position of equilibrium.

v=Aw

So v= 2 x 1

v=2ms^-1

Answered by William C. • Further Mathematics tutor

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In simple harmonic motion, where would the object have the largest speed. If the angular velocity is 2 rad s^-1, and the amplitude is 1m, what is the largest speed obtained by the object?

Related Further Mathematics A Level answers

Could you explain to me how proof by induction works?

Calculate: ( 2+i√(5) )( √(5)-i).

A curve C has equation y = x^2 − 2x − 24 x^(1/2), x > 0. Find dy/dx and d^2y/dx^2. Verify that C has a stationary point when x = 4

The complex number -2sqrt(2) + 2sqrt(6)I can be expressed in the form rexp(iTheta), where r>0 and -pi < theta <= pi. By using the form rexp(iTheta) solve the equation z^5 = -2sqrt(2) + 2sqrt(6)i.

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ABCya

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In simple harmonic motion, where would the object have the largest speed. If the angular velocity is 2 rad s^-1, and the amplitude is 1m, what is the largest speed obtained by the object?

Related Further Mathematics A Level answers

Could you explain to me how proof by induction works?

Calculate: ( 2+i√(5) )( √(5)-i).

A curve C has equation y = x^2 − 2x − 24 x^(1/2), x > 0. Find dy/dx and d^2y/dx^2. Verify that C has a stationary point when x = 4

The complex number -2sqrt(2) + 2sqrt(6)I can be expressed in the form r*exp(iTheta), where r>0 and -pi < theta <= pi. By using the form r*exp(iTheta) solve the equation z^5 = -2sqrt(2) + 2sqrt(6)i.

We're here to help

Company Information

Popular Requests

CLICK CEOP

MyTutor is part of the IXL family of brands:

IXL

Rosetta Stone

Wyzant

Education.com

Vocabulary.com

Emmersion

Thesaurus.com

Dictionary.com

SpanishDictionary.com

FrenchDictionary.com

Ingles.com

ABCya

© 2026 by IXL Learning

The complex number -2sqrt(2) + 2sqrt(6)I can be expressed in the form rexp(iTheta), where r>0 and -pi < theta <= pi. By using the form rexp(iTheta) solve the equation z^5 = -2sqrt(2) + 2sqrt(6)i.