By using an integrating factor, solve the differential equation dy/dx + 4y/x = 6x^-3 (6 marks)
Answer : y = 3/x2 + c/x4 Integrating factor is 4/x (1 mark) => I = eintegral (4/x) dx (1 mark) => I = x4 (1 mark). Using the formula, d/dx (x4 y) = 6x (1 mark)=> x4y = integral(6x)dx (1 mark for integrating). Rearranging gets to answer of y=3/x2 + c/x4. Where c is an arbitary constant (1 mark).
MD
Answered by Mark D. • Further Mathematics tutor
7320 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸Find the general solution to the differential equation; y'' + 4y' = 24x^2
Prove by induction the sum of n consecutive positive integers is of the form n(n+1)/2.
Prove by induction that for all positive integers n , f(n) = 2^(3n+1) + 3*5^(2n+1) , is divisible by 17.
I'm struggling with an FP2 First-Order Differential Equations Question (Edexcel June 2009 Q3) and the topic in general!