Calculate the kinetic energy of a proton moving at 95% of the speed of light. (c = 3x10^8 m/s, m_p = 1.67x10^-27 kg) [4 marks]

KE = 0.5mv[1] v = 3x10* 0.95 = 2.85x10[1] KE = 0.5 * 1.67x10-27 * (2.85x108)2  [1] KE = 6.782 x10-11 J [1]

TF
Answered by Tom F. Physics tutor

7091 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

An electron is accelerated through a uniform electric field of strength, E= 20 [N/C]. Determine the speed after the the electron travels 0.5 m from rest.


Why is it important that the baryon and lepton numbers of an interaction are conserved?


Initially, trucks A and B are travelling in opposite directions. A has mass 1000 kg and is travelling at speed 7ms^-1. B has mass 4000kg and is travelling at speed 2ms^-1. What is their speed and direction after collision if they move together?


The vehicle accelerates horizontally from rest to 27.8 m s–1 in a time of 4.6 s. The mass of the vehicle is 360 kg and the rider has a mass of 82 kg. 1. Calculate the average acceleration during the 4.6 s time interval.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning