Take quadratic equation x^2-6x+14=0 and its solutions a and b. What is a/b+b/a?

In this kind of exersise it is easy to use Viète's formula for quadratic equations: Let: a+b = S ab=P then x2 -Sx + P=0 In our case, S=6 and P=14 by multiplying the fractions we get: (aa)/(ab)+(bb)/(ab) = 2(a+b)/ab= 2S/P = 12/14 = 6/7

AM

Related Further Mathematics A Level answers

All answers ▸

How do I find the vector/cross product of two three-dimensional vectors?


How do you prove the formula for the sum of n terms of an arithmetic progression?


Show that G = {1, -1} is a group under multiplication.


Prove by induction that n! > n^2 for all n greater than or equal to 4.