Take quadratic equation x^2-6x+14=0 and its solutions a and b. What is a/b+b/a?
In this kind of exersise it is easy to use Viète's formula for quadratic equations: Let: a+b = S ab=P then x2 -Sx + P=0 In our case, S=6 and P=14 by multiplying the fractions we get: (aa)/(ab)+(bb)/(ab) = 2(a+b)/ab= 2S/P = 12/14 = 6/7
AM
Answered by Andreea-Lorena M. • Further Mathematics tutor
3396 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸Integrate x^2sin(x) between -pi and pi
Prove by induction that (n^3)-n is divisible by 3 for all integers n>0 (typical fp1 problem)
Calculate: ( 2+i√(5) )( √(5)-i).
Find the general solution to the second order differential equation x'' - 2x' + x = e^(2t).