Give the general solution to (d2y/dx2) - 2dy/dx -3y = 2sinx
Using the auxiliary equation t^2 - 2t - 3t = 0 t therefore is equal to 3 or -1. Using this value, a complementary function is derived. Y= Ae^(3x) + Be^(-x). Finally, to fully solve, a particular integral of y = asinx + bcosx and differentiate it twice, to give equations for Dy/dx and (d2y/dx2). These can be substituted into the initial differential equations to find the values of a and b, Which are -2/5 and 1/5 respectively. The answer is then the complementary function plus the solution to the particular integral y = Ae^(3x) + Be^(-x) + (1/5)cosx - (2/5)sinx
BY
Answered by Bradley Y. • Further Mathematics tutor
10341 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸Given M = [[-2,6],[1,3]], find P and D such that M = PDP^(-1) where D is a diagonal matrix
Prove by induction the sum of n consecutive positive integers is of the form n(n+1)/2.
Why is the integral of 1/sqrt(1-x^2)dx = sin^{-1}(x)?
Find the stationary points of the function z = 3x(x+y)3 - x3 + 24x