To differentiate a simple equation: y= 4x^3 + 7x
y = 4x^3 + 7 x
Recall: to differentiate any function of the form y = x^n
dy/dx = y' = n x^(n-1)
Hence if y = 4x^3 + 7x
dy/dx = 4 ( 3x^3 -1) + 7x^(1-1)
= 12 x^2 + 7
YS
Answered by Yusuf S. • Further Mathematics tutor
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