To differentiate a simple equation: y= 4x^3 + 7x

y = 4x^3 + 7 x

Recall: to differentiate any function of the form y = x^n

dy/dx = y' = n x^(n-1)

Hence if y = 4x^3 + 7x

dy/dx = 4 ( 3x^3 -1) + 7x^(1-1)          

= 12 x^2 + 7

YS
Answered by Yusuf S. Further Mathematics tutor

6479 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Point A lies on the curve y=3x^2+5x+2. The x-coordinate of A is 2. Find the equation of the tangent to the curve at the point A


f(x) = 2x^3+6x^2-18x+1. For which values of x is f(x) an increasing function?


How would I solve the following equation d^2x/dt^2 + 5dx/dt + 6x = 0


Use the factor theorem to show that (x-1) is a factor of x^3 - 3x^2 -13x + 15


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences