To differentiate a simple equation: y= 4x^3 + 7x
y = 4x^3 + 7 x
Recall: to differentiate any function of the form y = x^n
dy/dx = y' = n x^(n-1)
Hence if y = 4x^3 + 7x
dy/dx = 4 ( 3x^3 -1) + 7x^(1-1)
= 12 x^2 + 7
YS
Answered by Yusuf S. • Further Mathematics tutor
7631 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Using differentiation, show that f(x) = 2x^3 - 12x^2 + 25x - 11 is an increasing function.
What is the range of solutions for the inequality 2(3x+1) > 3-4x?
Why is it that when 'transformation A' is followed by 'transformation B', that the combined transformation is BA and not AB?
Find any stationary points in the function f(x) = 3x^2 + 2x