Are we able to represent linear matrix transformations with complex numbers?

Absolutely. Consider a point (a,b). This may be represented by the complex number a+bi and also by the column vector (a;b), where the semicolon means 'new line'.
To translate the point by +(c,d), in complex numbers, this is done by adding c+di to a+bi. In 2D space, this is done by adding (c;d) to (a;b).
To scale the point by a factor of r, in complex numbers, this is done by multiplying by r. In 2D space, we do the very same thing.
To rotate the point about (0,0) by angle t in the counterclockwise direction, in complex numbers, we do this by multiplying by e^it. In 2D space, we multiply on the left hand side by the matrix ((cost,-sint);(sint,cost)).
To conclude, if we were to translate a point (a,b) by +(c,d), scale it by factor r and rotate it about the origin by angle t in the counterclockwise direction, then the following are two representations of it:
(a+bi)(re^it)+(c+di)
r((cost,-sint);(sint,cost))(a;b)+(c;d)

JO

Related Further Mathematics A Level answers

All answers ▸

How to multiply and divide by complex numbers


Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form


P(A)=0.2, P(A|B) = 0.3 and P(AuB)=0.6. Find i P(B) ii P(B'|A')


Find the equation of the tangent to the curve y = exp(x) at the point ( a, exp(a) ). Deduce the equation of the tangent to the curve which passes through the point (0,1) .