Are we able to represent linear matrix transformations with complex numbers?

Absolutely. Consider a point (a,b). This may be represented by the complex number a+bi and also by the column vector (a;b), where the semicolon means 'new line'.
To translate the point by +(c,d), in complex numbers, this is done by adding c+di to a+bi. In 2D space, this is done by adding (c;d) to (a;b).
To scale the point by a factor of r, in complex numbers, this is done by multiplying by r. In 2D space, we do the very same thing.
To rotate the point about (0,0) by angle t in the counterclockwise direction, in complex numbers, we do this by multiplying by e^it. In 2D space, we multiply on the left hand side by the matrix ((cost,-sint);(sint,cost)).
To conclude, if we were to translate a point (a,b) by +(c,d), scale it by factor r and rotate it about the origin by angle t in the counterclockwise direction, then the following are two representations of it:
(a+bi)(re^it)+(c+di)
r((cost,-sint);(sint,cost))(a;b)+(c;d)

JO

Related Further Mathematics A Level answers

All answers ▸

FP3- Find the eigenvalues and the eigenvector for the negative eigenvalue, from this 2x2 matrix of columns (2,1) and (3,0)


Differentiate arctan of x with respect to x.


Prove by induction that 6^n + 4 is divisible by 5 for all integers n >= 1


How do I use proof by induction?