An electron of mass 9.11x10^(-31) is fired from an electron gun at 7x10^6 m/s. What size object will the electron need to interact with in order to diffract?

Momentum of electron=mv=6.377x10^-24 kg m/s

λ=h/mv=6.63x10-34/6.377x10-24=1.039...x10-10=1x10-10

JG
Answered by Jozefina G. Physics tutor

3347 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Bismuth-208, which has an atomic mass of 208u and 83 protons in the nucleus, decays through the emission of 2 alpha particles and a beta-positive particle. What isotope results from this decay?


Where does the formula for gravitational potential come from? Why the minus sign?


What are Newton's 3 laws of motion?


How would I derive Kepler's third law from Newton's law of gravitation and the equations of circular motion?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning