2 resistors of resistances 150 ohms and 5000 ohms respectively are in series with each other. They both are also in parallel with a 1000 ohm resistor. What is the total resistance?

Firstly, you should start by working out the total resistance for the 150 ohm and 5000 ohm resistors which are in series: -In series the total resistance is given as the sum of the resistance of each individual resistor (RT=R1+R2+R3...). -Therefore the total resistance of the 150 ohm and 5000 ohm resistors is 5150 ohms (150+5000=5150)  Imagine this total resistance of the resisitors in series (5150 ohms) being a resistor that replaces both the 150 ohm and 5000 ohm resistors. Now try working out the total resistance in parallel: -In parallel the reciprocal of the total resistance is given as the sum of the reciprocal of resistance for each individual resistor (1/R= 1/R+ 1/R+ 1/R...) -Therefore the reciprocal of the total resistance is 1/5150 + 1/1000 = 123/103000So to obtain the total resistance divide 1 by this value (as it is a reciprocal) to get a resitance of 103000/123 ohms which is equivalent to 837.4 ohms (4 s.f.)

GJ
Answered by Gaggan J. Physics tutor

2237 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A ball is thrown out of a window 18m off the ground. It is thrown horizontally at 0.5m/s. Show that it takes about 2s to reach the ground


A projectile is launched with a speed of 10m/s at an angle 30 degrees from the positive x axis. What is the range of the projectile?


"An inclined plane at an angle of 25 degrees to the horizontal has a pulley at its top. A 30kg block on the plane is connected to a freely hanging 20kg block by means of a cord passing over the pulley. From rest how far will the 20kg block fall in 2s?


Two electrons are a distance r apart, the first electron exerts a force F on the second electron. a) What force does the second electron exert on the first? b) In terms of r, at what distance is the force that the first electron exerts on the second F/9?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning