In one second a mass of 210 kg of air enters at A. The speed of this mass of air increases by 570 m s–1 as it passes through the engine. Calculate the force that the air exerts on the engine.
F = M x A (A= (V-U)/T) F = 210 x 570 F = 119,700 N
SG
F = M x A (A= (V-U)/T) F = 210 x 570 F = 119,700 N
