How do I solve a simultaneous equation with more unknowns than equations?

If a set of equations has more unknowns than equations, you cannot get a value for each unknown. However, you can find the relationships between the variables.Start by rearranging one variable in terms of the others and then plug that equation into the others, eliminating one variable. You will then be able to link the rest of the variables together in terms of each other.Finally, set one variable as a parameter, say u, and give the values of all the variable in terms of that uniting parameter.For example, you will end up with something like:x = 2u - 1y = 1/2u + 4z = u

HM
Answered by Hayden M. Further Mathematics tutor

4475 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

For a homogeneous second order differential equation, why does a complex conjugate pair solution (m+in and m-in) to the auxiliary equation result in the complementary function y(x)=e^(mx)(Acos(nx)+Bisin(nx)), where i represents √(-1).


Given that abc = -37 + 36i; b = -2 + 3i; c = 1 + 2i, what is a?


I don't understand how proof by mathematical induction works, can you help?


How would go about finding the set of values of x for which x+4 > 4 / (x+1)?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences