Using Newton's law of universal gravitation, show that T^2 is proportional to r^3 (where T is the orbital period of a planet around a star, and r is the distance between them).

(Lets consider a simple planetary system composed of a planet orbiting a star. the gravitational force between the two is given by F=(GMm)/(r2). Assuming the planet also moves in a circular orbit, we can consider the centripetal force, F=mω2r. As both gravitational and centripetal forces act in the same direction, we can equate them to find (GMm)/(r2)=mω2r.
We note that 'm' cancels and we can divide through by 'r' to arrive at GM/r32. ω is simply angular frequency given by ω =2π/T. Substituting this into our expression we find that GM/r3= 4π2/T2.After some simple rearranging, we note that  T=(4π2r3)/(GM). So  T2 is indeed proportional to  r3 . This simple statement is known as Kepler's third law of planetary motion.

KS
Answered by Karanvir S. Physics tutor

27865 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A railway car of mass m1 travelling at a velocity of v1 collides with a second car of mass m2 travelling at v2 and the two join together. What is their final velocity?


What is the general equation for the alpha-decay of a nucleus X, with nucleon number A and proton number Z, into nucleon Y??


What is the minimum initial velocity necessary for an object to leave Earth?


What is the maximum speed of an electron emitted from a metal surface with a threshold frequency of 5.706*10^(14) by light with a wavelength of 350nm?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning