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Differentiate x = sinhy with respect to x

x = sinhy=> dx/dy = coshycosh²y - sinh²y = 1=> sqrt(1 + sinh²y) = coshythus dx/dy = sqrt(1 + sinh²y)and dy/dx = 1/sqrt(1 + sinh²y)hence dy/dx = 1/sqrt(1+x²)

Answered by Ayush N. • Further Mathematics tutor

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