Differentiate x = sinhy with respect to x
x = sinhy=> dx/dy = coshycosh2y - sinh2y = 1=> sqrt(1 + sinh2y) = coshythus dx/dy = sqrt(1 + sinh2y)and dy/dx = 1/sqrt(1 + sinh2y)hence dy/dx = 1/sqrt(1+x2)
AN
Answered by Ayush N. • Further Mathematics tutor
3417 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸Prove that 27(23^n)+17(10^2n)+22n is divisible by 11 for n belongs to the natural numbers
For what values of x is Cosh^2(x) - Sinh(x) = 5 Give your answer in the form of a logarithm
Using de Moivre's theorem demonstrate that "sin6x+sin2x(16(sinx)^4-16(sinx)^2+3)"
How do you find the derivative of arcsinx?