(x+4)((x^2) - kx - 5) is expanded and simplified. The coefficient of the x^2 term twice the coefficient of the x term. Work out the value of k.

(x + 4) (x2 - kx - 5) = x3 - kx2 - 5x + 4x2 - 4kx - 20 = x3 + (4-k)x2 + (-5-4k)x - 20.The coefficients are: (4-k) of x2 and (-5-4k) of x. Now we can write the equation:(4-k) = 2(-5 - 4k) /expand4 - k = -10 - 8k /+8k4 + 7k = -10 /-47k = -14 /divide by 7k = -2

MF

Related Further Mathematics GCSE answers

All answers ▸

Make y the subject of the formula x = SQRT((y+1)/(y-2))


Find the tangent to the equation y=x^2 -2x +4 when x=2


Find the gradient of the line x^2 + 3x - 6 at the point (5,34)


Given that xy=2 and y=3x+5, find x and y. Do not use trial and improvement.