If photons of wavelength 0.1nm are incident on a 2m x 2m Solar Panel at a rate of 2.51x10^15s^-1, calculate the intensity, I, of the photons on the Solar Panel.
If wavelength = 0.1nm, we know (as E=hc/λ), the energy provided by each photon, E= 1.99x1015 J .Therefore, if they hit the panel at a rate of 2.51x1015s-1, we know Power = Energy x Rate, =4.99WIntensity, I = Power / Area, = 4.99W/(2m x 2m)Therefore, I=1.25Wm-2
SH
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