Use de Moivre’s theorem to show that, (sin(x))^5 = A sin(5x) + Bsin(3x) + Csin(x), where A , B and C are constants to be found.
State de Moivre's theorem. Use n =5 and solve. I'll show this on the whiteboard.
RM
Answered by Robbie M. • Further Mathematics tutor
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