Calculate the time taken for 1000L of water at rtp to be heated to 40degrees celsius using a 40kW heater

First the starting parameters of the fluid should be calculated, so at rtp the density of water is 1kg/L therefore mass is 1000kg and the temperature is 20 degrees C. The next step would be to plug these values into Q=mc(t2-t1), as we are given Q, m, and c is 4200J/KgK the change in temperature can be calculated from Q/mc = 0.0095degrees celsius. As the figure given is in watts this is therefore the temperature change per second, therefore the overall change divided by the change per second will give the overall time required which is 2100 seconds or 35 mins.

CA
Answered by Cameron A. Physics tutor

3278 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

How do I convert between eV and J


Name an experiment proving that light is wave and one that is proving that light consists of particles.


2 resistors of resistances 150 ohms and 5000 ohms respectively are in series with each other. They both are also in parallel with a 1000 ohm resistor. What is the total resistance?


What is escape velocity?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning