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find the diffrential of 3sin2x+4cos2x

dy/dx=6cos2x-8sin2xExplanation: cos x difrentiates to -sinx, we must times the coefficient of cos2x,(4) , by the differential of 2x (ie 2), giving -(4x2)sin2x.Similarly, sinx differentiates cosx, so using the same method, the sin term differentiates to (3x2)cos2x.

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