Why is the integral of a function the area?

Say you have two functions, A and B, and A is the gradient of B. That is to say, A is as high as B is steep (at any point). Equally, A is as high as the rate of change of B (at any point). Now let’s say we want to find a function that tells us the area under the curve A. Since the area under the curve A will increase as fast as A is high (think: if A is really high, then moving even a little along in x will result in a massive change in area still), we must be looking for a function which is increasing as fast as A is high. Rephrasing this a little bit, we want a function whose gradient (rate of increase) is as high as A is, which from our definition of a derivative is exactly the function B since A is the gradient of B. Thus, to find the area under a function A, we are always looking for the function B, which when differentiated, produces A, and so is the integral of A.

MC
Answered by Madison C. Maths tutor

3261 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Using methods of substitution solve the following simultaneous equations: y - 2x - 1 = 0 and 4x^2 + y^2 - 25 = 0


Use integration by parts to find the integral of xsinx, with respect to x


Find the coordinates of the point of intersection between the line L:(-i+j-5k)+v(i+j+2k) and the plane π: r.(i+2j+3k)=4.


(a) Express (1+4*sqrt(7))/(5+2*sqrt(7)) in the form a+b*sqrt(7), where a and b are integers. (b) Then solve the equation x*(9*sqrt(5)-2*sqrt(45))=sqrt(80).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning