x^2 - 5x - 12 = 2, solve for x

RHS should always be 0 so start by taking that across.Now we want two numbers, they need to add up to make - 5 and multiply to make -14.Solve for this and we get -7 and +2.Use this information to factorise: (x - 7)(x + 2) = 0One or the other bracket must equal 0 for this to be true, so x must equal 7 or - 2.Then go on to explain quadratic formula for cases where factorisation is not so easy.

PS

Related Maths GCSE answers

All answers ▸

You are given sets A: {2,4,6,8,10,12} and B: {1,3,5,7,9,11} explain why A∩B = ∅


Solve these simultaneously to find values for a and b: 6a + b = 16 and 5a - 2b = 19


1a) Simplify 2a^3 x a^5 1b) (4x^2)^3 1c) 2(3y+1) - 3(y-4)


x/(2x-3) + 4/(x+1) =1 [5 mark question]