What is the polar form of the equation: x^2+y^2 =xy+1
Using Pythagoras, x2 + y2 = r2.Using basic trigonometry, x = rsinθ and y = rcosθ.
xy + 1 = r2sinθcosθ + 1 = (1/2)r2sin2θ + 1
Subbing in both halves and doubling gives:2r2 = r2sin2θ + 2
-> r2(2 - sin2θ)r2 = 2
-> r2 = 2/(2-sin2θ)
HW
Answered by Hansen W. • Further Mathematics tutor
5692 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸Find the shortest distance between the lines r = (1, 5, 6) + y(-2, -1, 0) and r = (1, 7, -3) + z(2, 0, 4)
Why does e^ix = cos(x) + isin(x)
Integrate the function f(x) = x ln (x) over the interval [1,e].
Are the integers a group under addition? How about multiplication?