What is the polar form of the equation: x^2+y^2 =xy+1

Using Pythagoras, x2 + y2 = r2.Using basic trigonometry, x = rsinθ and y = rcosθ.
xy + 1 = r2sinθcosθ + 1 = (1/2)r2sin2θ + 1
Subbing in both halves and doubling gives:2r2 = r2sin2θ + 2
-> r2(2 - sin2θ)r2 = 2
-> r2 = 2/(2-sin2θ)

HW
Answered by Hansen W. Further Mathematics tutor

4613 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Find the square root of i


How do I differentiate tan(x) ?


Why is the integral of 1/sqrt(1-x^2)dx = sin^{-1}(x)?


Find the general solution to the differential equation y'' + 4y' + 3y = 6e^(2x) [where y' is dy/dx and y'' is d^2 y/ dx^2]


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning