A car of mass m travelling with a velocity v comes to rest over a distance d in time t. The constant frictional force acting on the car while it is braking is found using:

Newton's Second Law: F=maa=v-u/tUsing SUVAT equations: v2= u2+2asv (final velocity)=0 u(inital velocity)= v s=d Rearranging gives: -v2=2ad a=-v2/2d Therefore F= -mv2/2dNegative sign suggests the car is slowing down (negative acceleration)



GH
Answered by Ghafoor H. Physics tutor

7223 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A car of mass 800 kg is accelerated horizontally by constant net force of 1920 N for 9 s. It then breaks for 2 s, but drives off a 5 m high cliff. If μ = 0.85, what is the total horizontal distance travelled by car and its velocity? Ignore air resistance.


find and symplify the following. Integrate ( 2x^5 - 1/(4x^3)- 5 )dx


When does a pendulum bob move fastest and why?


How am I going to remember all of the particles I need to know? (A-level Physics)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences