An electron is traveling at a velocity of 500m/s perpendicular to a uniform magnetic field. A force of magnitude 4.32 x10^(-16) N is acting on the electron, what is the magnetic flux density of the field?

F=BQv so B=F/Qv (Q is the charge of an electron, 1.6 x10-19 C) so B=4.32 x10-16 / (1.6 x10-19 x 500) = 5.4 T

CJ
Answered by Christian J. Physics tutor

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