An electron is traveling at a velocity of 500m/s perpendicular to a uniform magnetic field. A force of magnitude 4.32 x10^(-16) N is acting on the electron, what is the magnetic flux density of the field?

F=BQv so B=F/Qv (Q is the charge of an electron, 1.6 x10-19 C) so B=4.32 x10-16 / (1.6 x10-19 x 500) = 5.4 T

CJ
Answered by Christian J. Physics tutor

1980 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Draw a diagram of the forces acting on the rocket as it flies vertically upwards, the rocket is flying through air not a vacuum (it's not in space yet!)


Explaining how capacitors work


Why does water stay in the bucket if it is swung through a loop fast enough?


What determines the acoustic impedance of a material and why is it useful in understanding ultrasound imaging?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning