A pipe has one open and one closed end. Determine the ratio of the frequency of the first harmomic to that of the next harmonic.

The first harmonic has wavelength λ1 = 4L and the next harmonic has wavelength λ2 = 4L/3. Hence :f1/f2 = (4L/3)/4L = 1/3

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Answered by Pablo M. Physics tutor

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