An electron is moving with speed 2x10^5ms-1 through a magnetic field of strength 0.5T. If the electrons velocity is perpendicular to the direction of the magnetic field, what is the magnitude of the force felt by the electron?

F = qv x B = qvB sin(O). q is the electrons charge = 1.6x10^-19 C. v is the electrons speed = 2x10⁵ ms^-1 . B is the magnetic field strength = 0.5 T. O is the angle between the electrons velocity vector and the magnetic field vector. Velocity is perpendicular to field so O = 90 degrees, sin(90)=1 therefore: F=qvB. Plugging the values into the equation we have :F= 1.6x10^-19 x 2x10⁵ x 0.5 Cms^-1 T Therefore F=1.6x10^-14 N