A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.

The gradient of a curve at a point is given by dy/dxDifferentiate the equationplug in the valuesdy/dx = 2ax + 3x = -1, dy/dx = -5-5 = 2a*-1 + 38 = 2aa = 4

SE

Related Further Mathematics GCSE answers

All answers ▸

Show that 2cos^2(x) = 2 - 2sin^2(x) and hence solve 2cos^2(x) + 3sin(x) = 3 for 0<x<180


A curve has equation: y = x^3 - 3x^2 + 5. Show that the curve has a minimum point when x = 2.


How can you divide an algebraic expression by another algebraic expression?


Find the General Second Order Differential Equation Using Substitution (A2 Further Maths)