A curve has equation y = ax^2 + 3x, when x= -1, the gradient of the curve is -5. Work out the value of a.

The gradient of a curve at a point is given by dy/dxDifferentiate the equationplug in the valuesdy/dx = 2ax + 3x = -1, dy/dx = -5-5 = 2a*-1 + 38 = 2aa = 4

SE
Answered by Salma E. Further Mathematics tutor

5431 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Can you explain rationalising surds?


Find the x and y coordinates of the minimum of the following equation: y = x^2 - 14x + 55.


If y=(x^2)*(x-10), work out dy/dx


Find the definite integral of f(x) = 12/(x^2+10x+21) with limits [-1,1]. Give your answer to 2 decimal places.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning