A person swims from a depth of 0.50 m to a depth of 1.70 m below the surface of the sea. density of the sea water = 1030 kg/m^3 gravitational field strength = 9.8 N/kg Calculate the increase in pressure on the swimmer. Give the Unit.

ΔP = Δh ρ g Δh = 1.7 - 0.5 = 1.2 m ρ = 1030 kg/m^{3}g = 9.8 N/kg ΔP = 1.2 (m) x 1030 (kg/m^{3}) x 9.8 (N/kg) = 12,112.8 N/m^{2} = 12,112.8 Pa