A person swims from a depth of 0.50 m to a depth of 1.70 m below the surface of the sea. density of the sea water = 1030 kg/m^3 gravitational field strength = 9.8 N/kg Calculate the increase in pressure on the swimmer. Give the Unit.
ΔP = Δh ρ g
Δh = 1.7 - 0.5 = 1.2 m ρ = 1030 kg/m3g = 9.8 N/kg
ΔP = 1.2 (m) x 1030 (kg/m3) x 9.8 (N/kg)
= 12,112.8 N/m2 = 12,112.8 Pa
