Given M = [[-2,6],[1,3]], find P and D such that M = PDP^(-1) where D is a diagonal matrix

We are given M = [[-2,6],[1,3]], with columns [-2,6] and [1,3]. To find P and D, eigenvalues and eigenvectors must be calculated, as D is defined to be the matrix whose diagonal is comprised of the eigenvalues of M in some order, and P is the matrix of eigenvectors corresponding to the eigenvalues order. We know if e is an eigenvalue and v is an eigenvector, Mv = ev, so Mv - ev = 0 vector, and (M-eI)v = 0 vector, where I is the identity matrix. M-eI has to have determinant 0, so we can solve this equation allowing e to be an unknown variable. by solving for e we obtain e = 4,-3. Returning to the previous equation, (M-eI)v = 0 vector, all that needs to be done is find v for each e. substitute e in the equation, and one can solve for v. To finish, D would be [[4,0],[0,-3]] and P would be [[1,6],[-1,1]]

HR

Related Further Mathematics A Level answers

All answers ▸

For a homogeneous second order differential equation, why does a complex conjugate pair solution (m+in and m-in) to the auxiliary equation result in the complementary function y(x)=e^(mx)(Acos(nx)+Bisin(nx)), where i represents √(-1).


Using the substitution u = ln(x), find the general solution of the differential equation y = x^2*(d^2(y)/dx^2) + x(dy/dx) + y = 0


What are the different forms of complex numbers and how do you convert between them?


Find the square root of i