Solve these simultaneous equations: 3xy = 1, and y = 12x + 3

From first equation: 3xy = 1 => x = 1/(3y)Substitute expression for x into second equation: y = 12x + 3 => y = 12(1/3y) + 3 = 4/y +3Multiply through by y: y2 = 4 + 3y => y2 - 3y - 4 = 0Factorise: (y-4)(y+1) = 0 => y = 4, y = -1 are solutionsx = 1/3y = 1/12, -1/3
Solutions are (1/12,4) and (-1/3, -1)

HM
Answered by Hallam M. Further Mathematics tutor

2083 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Find the General Second Order Differential Equation Using Substitution (A2 Further Maths)


Given a^2 < 4 and a+2b = 8. Work out the range of possible values of b. Give your answer as an inequality.


Find the coordinates of the minimum point of the function y=(x-5)(2x-2)


Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences