A particle is moving in a straight line from A to B with constant acceleration 4m/s^2. The velocity of the particle at A is 3m/s in the direction AB. The velocity of the particle at B is 18m/s in the same direction/ Find the distance from A to B.
First draw a diagram to see the set-up.Then look at SUVAT to see which values we have been given. In this case it is a=4, u=3,v=18 and s=?. The only letter not used from SUVAT is the t so we use the formula without... v2=u2+2as. Fill in the numbers 182=32+2 x 4 x s324 = 9+ 8s. Rearranges = (324-9)/8 = 39.375 m
AK
Answered by Adam K. • Further Mathematics tutor
3443 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸A straight line passes trough the points A(-4;7); B(6;-5); C(8;t). Use an algebraic method to work out the value of t.
How would you differentiate x^x?
Find any stationary points in the function f(x) = 3x^2 + 2x
The equation of a curve is y = x^2 - 5x. Work out dy/dx