A particle is moving in a straight line from A to B with constant acceleration 4m/s^2. The velocity of the particle at A is 3m/s in the direction AB. The velocity of the particle at B is 18m/s in the same direction/ Find the distance from A to B.

First draw a diagram to see the set-up.Then look at SUVAT to see which values we have been given. In this case it is a=4, u=3,v=18 and s=?. The only letter not used from SUVAT is the t so we use the formula without... v2=u2+2as. Fill in the numbers 182=32+2 x 4 x s324 = 9+ 8s. Rearranges = (324-9)/8 = 39.375 m

AK
Answered by Adam K. Further Mathematics tutor

2593 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

A curve has equation y = x^2 - 7x. P is a point on the curve, and the tangent to the curve at P has gradient 1. Work out the coordinates of P.


Let Curve C be f(x)=(1/3)(x^2)+8 and line L be y=3x+k where k is a positive constant. Given that L is tangent to C, find the value of k. (6 marks approx)


What is the range of solutions for the inequality 2(3x+1) > 3-4x?


Prove that sin(x)^2 - 5cos(x)^2 = 6sin(x)^2 - 5


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences