A trolley of mass 0.75kg is running along a frictionless track at a constant speed of 0.7ms-1, as the trolley passes below a mass of 0.5kg the mass drops a short vertical distance onto the trolley. Calculate the new velocity of the trolley and mass.

Momentum = mass x velocityInitial momentum = 0.75 x 0.7 =0.525kgms-1Momentum is assumed conserved so final momentum = 0.525kgms-1So final mass = 0.5+0.75 = 1.25kgSo final velocity = 0.525/1.25Final velocity = 0.42ms-1

AM
Answered by Alexander M. Physics tutor

2239 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A block of mass m is released from rest on a surface inclined at 30⁰ to the horizontal with a coefficient of friction of 0.3. How long does it take for the block to slide 1 m?


How should I structure my experiment report?


Can you explain the Work-Energy principle and how you can apply it in a simple situation such as a box sliding down a rough slope?


Describe how a stationary wave is formed and some of its properties.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning