A trolley of mass 0.75kg is running along a frictionless track at a constant speed of 0.7ms-1, as the trolley passes below a mass of 0.5kg the mass drops a short vertical distance onto the trolley. Calculate the new velocity of the trolley and mass.
Momentum = mass x velocityInitial momentum = 0.75 x 0.7 =0.525kgms-1Momentum is assumed conserved so final momentum = 0.525kgms-1So final mass = 0.5+0.75 = 1.25kgSo final velocity = 0.525/1.25Final velocity = 0.42ms-1
AM
Related Physics A Level answers
All answers ▸A ball is launched upwards at 30 degrees to horizontal with a velocity of 20 metres per second, how far does it travel before landing? (no air resistance)
What is the derivative of distance with respect to time.
A 10m long uniform beam is pivoted in its centre. A 30kg point mass is placed on one end of the beam. Where must a 50kg mass be placed in order to balance the beam?
How does having a rotating plate in a microwave help food to be heated eavenly?