Can you solve (2x-4)(x+1)=0?

All we need to do here is find the values of x that make each bracket zero.So2x-4=02x=4x=2andx+1=0x=-1

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HIGHER TIER a) Factorise the following equation into two bracket form: 2x^2-5x-12. b)2x^2-5x-12=0. Solve this equation to find the values of x, using your answer to part a). BONUS c) Sketch the function y=2x^2-5x-12, showing any x intercepts


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