Given the two equations [1](3x + 4y = 23) and [2](2x + 3y = 16), find the values of x and y

One way to find the values of x and y is to substitute the value of x into one of the equations. To sub in x we need to rearrange an equation to get x on its own. We can change the second equation to x = (16 - 3y)/2. We then sub this into equation 1 and get3[(16 - 3y)/2] + 4y = 23. Expanding this out gets 24 - (9/2)y + 4y = 23. -(9/2)y + 4y = -1 -1/2y = - 1 -y = -2 y = 2. This can then be substituted back into an equaiton to get x. Subbing back into equation 1 gets 3x + 8 = 23. 3x = 15 x = 5This can then be verified by subbing in our values back into equation 2 to check that our answers are correct.

SH
Answered by Stephen H. Maths tutor

3137 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve (2x+3)(4x-2)=0


A bag contains 10 apples. Three of the apples are green and seven of the apples are red. If an apple is pulled from the bag at random, what is the probability that the apple will be green?


Solve the equation x^2-10x+21=0


Simplify fully 3(3 – x) – 2(x – 4)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences